1.98t^2-28.8t-24=0

Solution for 1.98t^2-28.8t-24=0 equation:

1.98t^2-28.8t-24=0

a = 1.98; b = -28.8; c = -24;
Δ = b2-4ac
Δ = -28.82-4·1.98·(-24)
Δ = 1019.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28.8)-\sqrt{1019.52}}{2*1.98}=\frac{28.8-\sqrt{1019.52}}{3.96}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28.8)+\sqrt{1019.52}}{2*1.98}=\frac{28.8+\sqrt{1019.52}}{3.96}
$